Talk:Spherical polar coordinates: Difference between revisions

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I reverted changes by Anthony Argyriou because I don't know why he made them. Had  I known I would have strived for a compromise. --[[User:Paul Wormer|Paul Wormer]] 06:45, 16 January 2008 (CST)
I reverted changes by Anthony Argyriou because I don't know why he made them. Had  I known I would have strived for a compromise. --[[User:Paul Wormer|Paul Wormer]] 06:45, 16 January 2008 (CST)
== conventions ==
Somewhat delicate and possibly confusing issue. Note that there are two possibilities: one might
#exchange the ordering in the triple and *not* the meaning; i.e. one uses transform (r,phi,theta)->(x,y,z) with z=r*cos(theta) etc as in the basic convention
#exchange the meaning of the angles, placing theta on the (x,y)-plane, as the Weisstein quotation describes (regardless the order of the spherical triple).
As far as I can see, the option 1 is the Maple's choice (and BTW this is what I'm used to).
They write (u,v,w)->(x,y,z): [x = u*cos(v)*sin(w),  y = u*sin(v)*sin(w)  z = u*cos(w)]
I think it's too much to say that option 1 is a different convention (as the article suggests). But I'm not sure how to describe it in a clear way. [[User:Aleksander Stos|Aleksander Stos]] 10:56, 16 January 2008 (CST)

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I reverted changes by Anthony Argyriou because I don't know why he made them. Had I known I would have strived for a compromise. --Paul Wormer 06:45, 16 January 2008 (CST)

conventions

Somewhat delicate and possibly confusing issue. Note that there are two possibilities: one might

  1. exchange the ordering in the triple and *not* the meaning; i.e. one uses transform (r,phi,theta)->(x,y,z) with z=r*cos(theta) etc as in the basic convention
  2. exchange the meaning of the angles, placing theta on the (x,y)-plane, as the Weisstein quotation describes (regardless the order of the spherical triple).

As far as I can see, the option 1 is the Maple's choice (and BTW this is what I'm used to). They write (u,v,w)->(x,y,z): [x = u*cos(v)*sin(w), y = u*sin(v)*sin(w) z = u*cos(w)]

I think it's too much to say that option 1 is a different convention (as the article suggests). But I'm not sure how to describe it in a clear way. Aleksander Stos 10:56, 16 January 2008 (CST)