Square root of two: Difference between revisions
imported>Peter Lamonica No edit summary |
imported>Jitse Niesen (define "square root of 2", and state that x,y are in N (if they can be negative, it's not so clear what "smallest" means)) |
||
Line 1: | Line 1: | ||
The square root of two | The [[square root]] of two, denoted <math>\sqrt{2}</math>, is the positive number whose square equals 2. It is approximately 1.4142135623730950488016887242097. It provides a typical example of an [[irrational number]]. | ||
== In Right Triangles == | == In Right Triangles == | ||
Line 7: | Line 7: | ||
There exists a simple proof by contradiction showing that <math>\sqrt{2}</math> is irrational: | There exists a simple proof by contradiction showing that <math>\sqrt{2}</math> is irrational: | ||
Assume that there exists two numbers, <math>x, y \in \mathbb{ | Assume that there exists two numbers, <math>x, y \in \mathbb{N}</math>, such that <math>\frac{x}{y} = \sqrt{2}</math> and <math>x</math> and <math>y</math> represent the smallest such [[integer|integers]] (i.e., they are [[mutually prime]]). | ||
Therefore, <math>\frac{x^2}{y^2} = 2</math> and <math>x^2 = 2 \times y^2</math>, | Therefore, <math>\frac{x^2}{y^2} = 2</math> and <math>x^2 = 2 \times y^2</math>, | ||
Line 18: | Line 18: | ||
Since <math>k</math> is an integer, <math>y</math> must ''also'' be even. However, if <math>x</math> and <math>y</math> are both even, they share a common [[factor]] of 2, making them ''not'' mutually prime. And that is a contradiction. | Since <math>k</math> is an integer, <math>y</math> must ''also'' be even. However, if <math>x</math> and <math>y</math> are both even, they share a common [[factor]] of 2, making them ''not'' mutually prime. And that is a contradiction. | ||
[[Category:Mathematics Workgroup]] | |||
[[Category:CZ_Live]] |
Revision as of 20:51, 28 March 2007
The square root of two, denoted , is the positive number whose square equals 2. It is approximately 1.4142135623730950488016887242097. It provides a typical example of an irrational number.
In Right Triangles
The square root of two plays an important role in right triangles in that a unit right triangle (where both legs are equal to 1), has a hypotenuse of . Thus,
Proof of Irrationality
There exists a simple proof by contradiction showing that is irrational:
Assume that there exists two numbers, , such that and and represent the smallest such integers (i.e., they are mutually prime).
Therefore, and ,
Thus, represents an even number
If we take the integer, , such that , and insert it back into our previous equation, we find that
Through simplification, we find that , and then that, ,
Since is an integer, must also be even. However, if and are both even, they share a common factor of 2, making them not mutually prime. And that is a contradiction.