User:Dan Nessett/Sandboxes/Sandbox 4: Difference between revisions

Revision as of 10:58, 9 August 2010

$\pi ={\frac {3}{4}}{\sqrt {3}}+24\int _{0}^{1/4}{{\sqrt {x-x^{2}}}dx}$

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		<math>\pi=\frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx}</math>